Thursday, May 31, 2007

SequEnceS

We started our class with this 3 questions...
There are 2 different ways to find the answers for these questions.
For the first question, you add 3 to 5 to get 8, and then add 3 to 8 to get 11, and so on till you get the 110th term, but no one wants to do that. Here's the easier way...
On your calculator, press the "y=" button, (Make sure that your calculator is on "Seq" mode or "Sequence Mode".)

Your screen should look like this...Then enter...Then hit 2nd, Mode to exit to your main screen. Then enter u(110) (to enter u, press 2nd, 7 ) Press enter to get the 110th term which is 332.

For Question 2 you multiply every number by 2 to get the next number, conti
nue till you get the 21st term. To use your calculator, go back to your "y=" screen. Clear everything up except the nMin=1.

Then enter...
Now, go back to your main screen and enter u(21), then hit enter to get the 21st term which is 3145728.

For the 3rd question, add the 1st and 2nd number to get the 3rd number, then add the 2nd and 3rd number to get the 4th number, and so on. This sequence is called the "Fibonacci sequence" where each number is the sum of the two preceding numbers.

To use your calculator, go to your "y=" screen. Clear everything up except the nMin=1.

Then enter...Go back to your main screen and enter u(27), then hit enter to get the 27th term which is 196418.

Then we moved on to another question...
On this question we are now looking for the "term".
To answer this question without your calculator, Multiply each number by 2, then add 1 to the product. Do this until you end up with an answer of 1535.
But to use your calculator, go to your "y=" screen.

Then enter...
Then hit 2nd, Graph to get to the table. Scroll down till you end up with 1535.
So the term of 1535 in the sequence is 10.

This is the end of my scribe post... The next scribe is Kristel. ~(_8^(])

2 comments:

  1. Well i chose today because i couldnt do it tomarrow... so i cant... but since you have already done yours... umn .. cool!?

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