Im sorry guys if didn't post my scribe on tuesday's class, I'll post it tomorrow..............
NEXT SCRIBE IS Nadiya.......
Showing posts with label jOweLL. Show all posts
Showing posts with label jOweLL. Show all posts
Wednesday, June 6, 2007
Monday, May 14, 2007
bOb
Personal Finance_____one of the easiest unit that i've encountered....all you have to do is to read the question carefully and do a little thinking to solve the problem and i've also learned lots of things on this unit like the difference of buying and leasing a car, advantages and disadvantages and the mortage in buying a house and the most interesting part that I liked on this unit is on how you going to retire a millionaire.....
Wednesday, April 25, 2007
Scribe April 25, 2007
On our morning class we started out with a pre-test and right after that, Mr. K puts us in a group to share our answers and hand in one paper. But there wasnt enough time so we continued the group discussion in the afternoon.

And here are the questions & answers on our pretest this morning.
1.The vector represents a velocity of 50 km/h towards [030°]. What is 4v?
(a) 50 km/h towards [-120°] (b) 50 km/h towards [120°]
(c) 200 km/h towards [030°] (d) 200 km/h towards [120°]
(a) 50 km/h towards [-120°] (b) 50 km/h towards [120°]
(c) 200 km/h towards [030°] (d) 200 km/h towards [120°]
-> answer = c
=4x50 =200
the direction stays
2.The airspeed of an airplane is 300 km/h. A wind blows from due east at
50 km/h. In what direction does the plane need to head in order to travel
due north?
(a) [010°] (b) [296°] (c) [304°] (d) [350°]
50 km/h. In what direction does the plane need to head in order to travel
due north?
(a) [010°] (b) [296°] (c) [304°] (d) [350°]
-> answer = d
bec. if the wind is travelling due to east and the plane wants to go north the angle of the plane should be around 340-360 degrees....
3. Corrie and Allan are pulling on a rock with equal force, they are at an angle
of 40° to each other.
If the resultant vector has a force of 50 newtons, determine the magnitude of the force with which each is pulling.
of 40° to each other.
If the resultant vector has a force of 50 newtons, determine the magnitude of the force with which each is pulling.
- its a tail to tail diagram so we use the parallelogram method....
- the answer would be 140, in my diagram I add the 90 & 50 to get the result of the magnitude of the force.....
4. If the resultant force remains at 50 newtons, at what angle could Corrie and
Allan pull in order for Corrie to pull with double the force of Allan?
Allan pull in order for Corrie to pull with double the force of Allan?
- the two should pull at a 90 dgrees angle... bec if Allan is pulling 100N & Corrie pulling 50N...the resultant vector will be 50N by using the pythagorean theorem....
5. An airplane travels at a speed of 250 km/h in a direction 30° north of west for
one hour. It then travels at a speed of 300 km/h for 40 minutes in a direction
of 42° east of north. To return directly to its starting point, in what directionand what distance must the airplane travel?
one hour. It then travels at a speed of 300 km/h for 40 minutes in a direction
of 42° east of north. To return directly to its starting point, in what directionand what distance must the airplane travel?
-first change the velocity of the plane to distance...
250 x (60/60) ->60mins represents 1hr
= 250km
= 250km
300 x (40/60)
= 200km
- then punch in all the info into the calculator and use the trisolv2 program
-and the result would be like this
-The plane should head of Bearing 163.187 deg. (73.187 + 90) with a distance of 285.848 km.
I gues thats it for me.....
The next scribe will be Al Andrei.............
Friday, April 13, 2007
BOB
Our unit Statistic is confusin... because of many formulas and the different calculator command.... And some of the problem I dn't know how to do it, but yesterday's review and today's class really helped me.... now I kinda understand which formula im going to use or calculator commands in each problem..... I hope I dn't get confuse on tomorrow's test and atleast I could get 50% on the test....... ----->>> wishing u all best of luck!.... :S
Tuesday, April 3, 2007
Monday, March 12, 2007
Monday, March 12
Hello Guyz!.. In today’s class during the morning period we submitted our individual deadlines for our project (DEVELOPING EXPERT VOICES) and after that we started discussing about the new unit called STATISTICS. Statistics is the branch of mathematics that deals with the collection, organization, and interpretation of data. You noticed that our previous unit Probability has a connection to our new unit Statistics. These concepts will be combine to work with the Probability Distributions where the probability distributions gives the theoretical probability of each outcome of an experiment…
Then in the afternoon class we did an experiment where Mr. K gave us 4 coins and we toss it 12x and some toss it 13x to be a total of 200 trials, these experiments tells us the probability of having 4 all girls in a family.
THEORETICAL PROBABILITY
Having 0 girls --- P(0G) = 4! (1/2)^4 = 1 = 6.25%
4! 16
Having 1 girl -----P(1G) = 4! (1/2)(1/2)^3 = 4 = 25%
3! 16
Having 2 girls ----P(2G) = 4! (1/2)^2(1/2)^2 = 6 = 37.5%
(2!2!) 16
Having 3 girls ----P(3G) = 4! (1/2)^3(1/2) = 4 = 25%
3! 16
Having 4 girls ----P(4G) = 4! (1/2)^4 = 1 = 6.25%
4! 16
EXPERIMENTAL PROBABILITY
# Of Girls
0 = 18 18 = 9%
200
1 = 51 51 = 25.5%
200
2 = 69 69 = 34.5%
200
3 = 54 54 = 27%
200
4 = 10 10 = 5%
200
a total of 200 trials
We did this experiment 200x for our experimental probability to be close to our theoretical probability. Then we graph it to our calculator so we could see the difference of each one... just refer to the slide for the graph....
I gues thats it for me... and the next scribe will be cRiS_J
GuDLuCk oN tOmOrrOw's tEsT....
Then in the afternoon class we did an experiment where Mr. K gave us 4 coins and we toss it 12x and some toss it 13x to be a total of 200 trials, these experiments tells us the probability of having 4 all girls in a family.
THEORETICAL PROBABILITY
Having 0 girls --- P(0G) = 4! (1/2)^4 = 1 = 6.25%
4! 16
Having 1 girl -----P(1G) = 4! (1/2)(1/2)^3 = 4 = 25%
3! 16
Having 2 girls ----P(2G) = 4! (1/2)^2(1/2)^2 = 6 = 37.5%
(2!2!) 16
Having 3 girls ----P(3G) = 4! (1/2)^3(1/2) = 4 = 25%
3! 16
Having 4 girls ----P(4G) = 4! (1/2)^4 = 1 = 6.25%
4! 16
EXPERIMENTAL PROBABILITY
# Of Girls
0 = 18 18 = 9%
200
1 = 51 51 = 25.5%
200
2 = 69 69 = 34.5%
200
3 = 54 54 = 27%
200
4 = 10 10 = 5%
200
a total of 200 trials
We did this experiment 200x for our experimental probability to be close to our theoretical probability. Then we graph it to our calculator so we could see the difference of each one... just refer to the slide for the graph....
I gues thats it for me... and the next scribe will be cRiS_J
GuDLuCk oN tOmOrrOw's tEsT....
Wednesday, March 7, 2007
BOB
Wow we're almost done on our Probability unit.. This unit is a lot harder than on our previous unit Matrices and confusing too....Actually its not really that hard its just the questions that confuses me... But I understand it now but still confuse on some questions.... Oh well I'll just have to study hard on it so that I could just get at least 50% on the test...... >:)
Saturday, February 17, 2007
February 16, 2007
During our Friday class Mr. K inroduced to us the smartboard, then we had a pre-test in the morning & we were group into 4 & compared each others answer in the group. Then in the afternoon class Mr. K gave us some problem to solve. Obviously Mr.K didn't gave us any new lesson so im just going to solve one problem from the h.w. review from the book pg.89 #5.
- A young entrepreneur decides he will sell tank tops, short-sleeved T-shirts, long-sleeved T-shirts, and sweatshirts. The table below shows the cost to produce each item.
- A young entrepreneur decides he will sell tank tops, short-sleeved T-shirts, long-sleeved T-shirts, and sweatshirts. The table below shows the cost to produce each item.
Subscribe to:
Posts (Atom)

