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Monday, June 11, 2007
Today's Slides: June 11
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Friday, June 8, 2007
Today's Slides: June 8
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Friday, April 13, 2007
BOB
Thursday, April 12, 2007
BOB
Bob
Today's Slides: April 12
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Wednesday, April 11, 2007
BOB
-Britt<3
BOB
So i guess the first thing i would like to say about STATISTICS is that it has frustrated me more than once this term and that I am glad it is almost over.. One thing i noticed was that it was really difficult going through it once with the class and Mr.k. For a while i thought i could possibly fail this unit. The thing that i noticed though was that when i went though it a second time ( on my spare time of course) from the beginning of chapter to the end, it was so much easier because i already had the knowledge that Mr.k had already gave us in my mind. The text book gave me that extra little push into the "I-know-what-I-am-doing-now" zone. I still believe i might have some problems, this isn't an extra easy unit. But the text book helped.. its great to know its not just a paper weight AND it taught me some neat things. Like how i knew that you should clear the Lists and turn off the Y plots when you shade norm. So that's my little blurb about statistics.. GOOD LUCK ON YOUR TEST!!!
Today's Slides: April 11
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BOB
Tuesday, April 10, 2007
BOB
BOB
B O B
BOB
BOB
scribe
So it's tomorrow now! and Mr. K was there and we went over the pretest. aaand here it is.
and the next scribe is cris_J
Monday, April 9, 2007
Sunday, April 8, 2007
Confidence Interval
A confidence interval gives an estimated range of values which is likely to include an unknown population parameter, the estimated range being calculated from a given set of sample data.
We had this problem…
Some Senior 4 students in a large high school want to change a tradition at graduation. Instead of wearing the usual cap and gown, they want to wear formal clothes. A quick survey of 96 randomly selected students shows that 41 prefer formal wear.
To answer this question, construct a “confidence interval”, most often a “95% confidence interval”.
Find the probability (P), the mean (µ), and the standard deviation (σ) first.
p = 41 / 96
= 0.43
µ = n ∙ p
= 96 (0.43)
= 41.28
σ = √ n ∙ p ∙ (1 - p)
= √ 96 (0.43) (1 – 0.43)
= √ 23.5296
= 4.851
For data that have a normal distribution with mean and standard deviation, a 95% confidence interval is:
µ ± 1.96σ
This is the range of values that lie within 1.96 standard deviations of the mean. The probability that a particular data value lies in that range is 0.95. This is shown in the graph.
95% confidence interval = µ ± 1.96σ
= 41.28 ± 1.96 (4.851)
= 41.28 ± 9.508
= 41.28 – 9.508
= 31.772
or
= 41.28 + 9.508
= 50.788
We write it this way: (31.772, 50.788)
= (31.772 / 96) × 100
= 33%
= (50.788 / 96) × 100
= 53%
And we write it this way: (33%, 53%)
With 95% confidence, we know that between 33% and 53% of 96 students prefer formal wear.
Now, find the Margin of Error and Percent Margin of Error.
The margin of error is the proportion that we add to, and subtract from, the mean to construct the confidence interval.
For a 95% confidence interval: Margin of Error = ± 1.96σ
1.96 × 4.851 or 9.508 represents the half-width of the interval. This is the margin of error. To express this as a percent, we divide it by the sample size, which is 96, and multiply by 100.
% Margin of Error = ± (9.508 / 96) × 100
= ± 9.904%
Is it possible that a majority of students prefer formal wear?
** Yes, but not likely, because the high end of the 95% confidence interval is just 3% over the half of the sample size and the Margin of Error is a little bit high. When you conduct a survey, the smaller the Margin of Error, the better the results of the survey.
The next scribe is Donna (",)
Thursday, April 5, 2007
Today's Slides: April 5
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Monday, April 2, 2007
Statistics
The probability that a student owns a cd player is 3/5. If eight students are selected at random, what is the probability?
a) exactly 4 of them own a cd player
To do this we have to use "Binompdf." So if we want to do this on the calculator you press:
- 2nd, DISTR
- find Binompdf or if you have a TI-83 press 0
- Then we use the formula - Binompdf(# of Trials, Probability of success, # of success)
So it should look like this:
Binompdf(8, 3/5, 4)
You hit enter and your get .2322 or 23.22% and thats your probability.
We also learned how to Calculate probabilitys using normal approxamate of binomial distribution.
Example
A basketball player is successful on her freethrows 75% of the tim. Determine the probability that she makes at least 7/10 free throws.
So using normal approxamate of binomial distribution we have to know that:
- N = Number of trials = 10
- P = Probability of success = .75
- # of Success = 7
So we have to know thes three formulas to do this:
M = N*P
Failure = N(1-P)
S.T = Standard Deviation = S.D = Square root (M(1-P)
Z score = Z = (# of success - M)/S.D
Now we put all the info in and find the Z Score
we get the S.D of -0.3693. So now we use shadenorm to find the probabilty. So we go Shadenorm(-0.3651 , 5) and get the probability of 64.25%
Next scribe is Cris J.



