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Tuesday, June 12, 2007
Today's Slides: June 12
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Wednesday, May 30, 2007
BOB
BoB, Ivy
BOB
Tuesday, May 29, 2007
Periodic Functions
A tsunami(commonly called a "tidal wave" because its effect is rapid change in tide) is a fast-moving ocean wave caused by an underwater earthquake. The water first goes down form its normal level, then rises an equal distance above its normal level, and finally return ti its normal level. The period is about 15 minutes. Suppose that a tsunami with an amplitude of 10 metres approaches the pier at Honolulu, where the normal depth of the water is 9 metres.
For this problem we first need to construct a graph and fill in "DABC".

This is how we start our graph. It stated that the normal depth of the water if 9 metres therefore it is the average value of function(sinusoidal axis). It is where our graph will start. We then add 10 metres to the sinusoidal axis since the amplitude is 10. It tell us how far to go from the sinusoidal axis. This will give us the maximum(19 metres). We then find the minimum by subtracting 10 from 9(-1).
We can now construct the graph.
The graph first goes down since it is stated in the information that the water first goes down from its normal depth. This wave has an amplitude of 10(as stated earlier) therefore the wave goes down its minimum depth which is -1. It also says that it then goes back to its normal depth at the same equal time. Therefore we divide the whole period(which is 15 ) into 4 parts because it first goes down then up, then up again and finally down.
We can now find "DABC"
A= -10 ( amplitude. it is negative because the first movement of the wave is down)
B=2(pi)/15 ( determines the period , we place 15 because a period is every 15 mins)
C=0 (since the wave started at 0 minutes and at the sinusoidal axis, there is no horizontal shift)
D= 9 ( this tells us that the whole graph will move 9 metres up, it is the sinusoidal axis)
Now we can put these informations into an equation.
The amplitude
2 Pi(3.14) / 15 = o.42
The vertical shift\
A) Assuming that the depth of the wave varies sinusoidally with time as the tsunami passes, predict the depth of the water at the following times after the tsunami first reaches the pier.
i) 2 minutes ii) 4 minutes iii) 12 minutes
For this problem, we could just insert these times into the equation in place of x to determine the depth of the water. For example, this is the equation for 2 minutes:

We do the same for the rest, place the minutes in place of x.
B) According to your model, what will be the minimum depth of the water? How do you interpret this answer in terms of what will happen in the real world?
We can see the lowest depth of the water by looking at our graph. It is -1 since it is the lowest the wave can go. In the real world this is kind of confusing. How can the lowest depth be -1 , this would mean it digs under see bottom. Therefore we state it as , for lenght of time the wave is at its lowest, we can see the bottom.
C) The wavelenght of the water is the distance a crest of the wave travels in one period. It is also equal to the distance between two adjacent crests. If a tsunami travels at 800 kilometers per hour, what is the wavelenght?
For this question. it is stated that the the wave is traveling 800 km/h. In our graph, one period of the wave is 15 minutes. We found the answer for this question by cross multiply.
THE NEXT SCRIBE IS CHRIS A.!!!!
BOB
BOB
-Britt<3
BOB
Good luck on the test!
B o B
Good Luck to everyone... ~(_8^(])
BOB
Today's Slides: May 29
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Monday, May 28, 2007
B.O.B
BOB
BOB
Today's Slides: May 28
Here the are the others ...
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May 28
First period we reviewed for our test by doing some problems in groups. Question 1 as shown in the slides introduced some words that i have never heard of. First of all there were the words Perigee and Apogree;
Perigee means the closest point to something.
Apogree means the furthest point from something.
The first question asked "How does it take for the spaceship to go around the earth."- To answer this you are trying to find the period or (B)

- The next question was "What are the distances at the Perigree and the Apogree?"
To find the distance for the Perigree you take D-A or 550-450 = 100
To find the distance for the Apogree you take D+A or 550+450 = 1000
Question 2 is explained in the slides posted from today.
Period 2
We did our per-test.
The test is on Wednesday people and we start our final unit tomorrow.
The next scribe is Jowell.
Scribe, May 23,24 and 25
On May 23 and 24 we got two booklets in which we were supposed to work on independently for a new unit of Design and measurement. Basically the whole unit was summarized in these two booklets but Mr.K wasn't there and we had kind of a hard time recalling this methods because it's been so long.
On Friday, when Mr K came back there was really no talk about the unit we had done while he was away. He started off by reviewing what we had done so far in periodic functions ( the slides from the past classes) and reminded us that our exam was only about 19 days away.
In slide 1 we looked at putting all the information we had done so far to a problem.
Sorry I'll finish up later my pictures don't want to work
The next scribe Is........I think were starting a new cycle
Friday, May 25, 2007
Today's Slides: May 25
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Tuesday, May 22, 2007
Today's Slides: May 22
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